comment resoudre cette equation (x+1)2 -(x+1)(2x-3)=(x+1)(2x-3)-(x+1)(2x-3)
Mathématiques
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Question
comment resoudre cette equation
(x+1)2 -(x+1)(2x-3)=(x+1)(2x-3)-(x+1)(2x-3)
(x+1)2 -(x+1)(2x-3)=(x+1)(2x-3)-(x+1)(2x-3)
2 Réponse
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1. Réponse maudmarine
(x + 1) 2 - (x + 1) (2x - 3) = (x + 1) (2x - 3) - (x + 1) (2x - 3)
x + 2 - (2x² - 3x + 2x - 3) = 2x² - 3x + 2x - 3 - (2x² - 3x + 2x - 3)
x + 2 - 2x² + 3x - 2x + 3 = 2x² - 3x + 2x - 3 - 2x² + 3x - 2x + 3
- 2x² + x + 3x - 2x + 2 + 3 = 2x² - 2x² - 3x + 3x - 2x + 2x - 3 + 3
- 2x² + 2x + 5 = 0
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2. Réponse nonotata
si c est (x+1) multiplier par 2 cela donne
(x+1)2 -(x+1)(2x-3)=(x+1)(2x-3)-(x+1)(2x-3)
2x+2 -(2x²-3x+2x-3) = 0
2x+2-2x²+x+3 =0
-2x² +3x+5 =0