Mathématiques

Question

resoudre les equation suivante (4 eme)

a)3a-11=a+15 b)2-4b=-3b-5
c)-5a-3=a-15 d)7x-5=-3x+7
e)5x+6=3x+6 f)3x-5=3x+7

1 Réponse

  • 3a - 11 = a + 15
    3a - a = 15 + 11
    2a = 26
    a = 26/2
    a = 13

    2 - 4b = - 3b - 5
    2 + 5 = - 3b + 4b
    7 = b

    - 5a - 3 = a - 15
    - 3 + 15 = a + 5a
    12 = 6a
    12/6 = a
    2 = a

    7x - 5 = - 3x + 7
    7x + 3x = 7 + 5
    10x = 12
    x = 12/10
    x = 6/5

    5x + 6 = 3x + 6
    5x - 3x = 6 - 6
    2x = 0
    x = 0

    3x - 5 = 3x + 7
    3x - 3x = 7 + 5
    0x = 12
    Pas de solution

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