racine (x² + 6x + 6) ≥ |2x + 11l
Mathématiques
matytall2020
Question
racine (x² + 6x + 6) ≥ |2x + 11l
1 Réponse
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1. Réponse carlx7970
bonjour
(x² + 6x + 6) ≥ |2x + 11l
= x²+6x- |2x+11| ≥ -6
= x²+6x- (2x+11) ≥ -6 , 2x+11 ≥ 0
x²+6x- (-(2x+11)) ≥ -6 , 2x+11 < 0
= x € ⟨ -∞ , -5] u [ 1 , +∞ ⟩ , x ≥ -11 /2
x € R , x < -11/2
= x € [-11/2 , -5] u [ 1 , +∞⟩
x € ⟨ -∞ , -11/2 ⟩
x € ⟨ -∞ , -5] u [ 1 , +∞ ⟩
PS: €: c'est appartient